On the Existence of Free Ultrafilters on ω and on Russell-sets in ZF
Bulletin of the Polish Academy of Sciences. Mathematics (2015)
- Volume: 63, Issue: 1, page 1-10
- ISSN: 0239-7269
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topEleftherios Tachtsis. "On the Existence of Free Ultrafilters on ω and on Russell-sets in ZF." Bulletin of the Polish Academy of Sciences. Mathematics 63.1 (2015): 1-10. <http://eudml.org/doc/281273>.
@article{EleftheriosTachtsis2015,
abstract = {
In ZF (i.e. Zermelo-Fraenkel set theory without the Axiom of Choice AC), we investigate the relationship between UF(ω) (there exists a free ultrafilter on ω) and the statements "there exists a free ultrafilter on every Russell-set" and "there exists a Russell-set A and a free ultrafilter ℱ on A". We establish the following results:
1. UF(ω) implies that there exists a free ultrafilter on every Russell-set. The implication is not reversible in ZF.
2. The statement there exists a free ultrafilter on every Russell-set" is not provable in ZF.
3. If there exists a Russell-set A and a free ultrafilter on A, then UF(ω) holds. The implication is not reversible in ZF.
4. If there exists a Russell-set A and a free ultrafilter on A, then there exists a free ultrafilter on every Russell-set.
We also observe the following:
(a) The statements BPI(ω) (every proper filter on ω can be extended to an ultrafilter on ω) and "there exists a Russell-set A and a free ultrafilter ℱ on A" are independent of each other in ZF.
(b) The statement "there exists a Russell-set and there exists a free ultrafilter on every Russell-set" is, in ZF, equivalent to "there exists a Russell-set A and a free ultrafilter ℱ on A". Thus, "there exists a Russell-set and there exists a free ultrafilter on every Russell-set" is also relatively consistent with ZF.
},
author = {Eleftherios Tachtsis},
journal = {Bulletin of the Polish Academy of Sciences. Mathematics},
keywords = {axiom of choice; free filter on a set; free ultrafilter on a set; Russell-set; symmetric models of ZF},
language = {eng},
number = {1},
pages = {1-10},
title = {On the Existence of Free Ultrafilters on ω and on Russell-sets in ZF},
url = {http://eudml.org/doc/281273},
volume = {63},
year = {2015},
}
TY - JOUR
AU - Eleftherios Tachtsis
TI - On the Existence of Free Ultrafilters on ω and on Russell-sets in ZF
JO - Bulletin of the Polish Academy of Sciences. Mathematics
PY - 2015
VL - 63
IS - 1
SP - 1
EP - 10
AB -
In ZF (i.e. Zermelo-Fraenkel set theory without the Axiom of Choice AC), we investigate the relationship between UF(ω) (there exists a free ultrafilter on ω) and the statements "there exists a free ultrafilter on every Russell-set" and "there exists a Russell-set A and a free ultrafilter ℱ on A". We establish the following results:
1. UF(ω) implies that there exists a free ultrafilter on every Russell-set. The implication is not reversible in ZF.
2. The statement there exists a free ultrafilter on every Russell-set" is not provable in ZF.
3. If there exists a Russell-set A and a free ultrafilter on A, then UF(ω) holds. The implication is not reversible in ZF.
4. If there exists a Russell-set A and a free ultrafilter on A, then there exists a free ultrafilter on every Russell-set.
We also observe the following:
(a) The statements BPI(ω) (every proper filter on ω can be extended to an ultrafilter on ω) and "there exists a Russell-set A and a free ultrafilter ℱ on A" are independent of each other in ZF.
(b) The statement "there exists a Russell-set and there exists a free ultrafilter on every Russell-set" is, in ZF, equivalent to "there exists a Russell-set A and a free ultrafilter ℱ on A". Thus, "there exists a Russell-set and there exists a free ultrafilter on every Russell-set" is also relatively consistent with ZF.
LA - eng
KW - axiom of choice; free filter on a set; free ultrafilter on a set; Russell-set; symmetric models of ZF
UR - http://eudml.org/doc/281273
ER -
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