Generalization of an identity involving the generalized Fibonacci numbers and its applications.
Mohammad Farrokhi, D.G. (2009)
Integers
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Mohammad Farrokhi, D.G. (2009)
Integers
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Alexey Stakhov (2012)
Visual Mathematics
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Ahmet Daşdemir (2019)
Annales Universitatis Paedagogicae Cracoviensis. Studia Mathematica
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To date, many identities of different quaternions, including the Fibonacci and Lucas quaternions, have been investigated. In this study, we present Gelin-Cesáro identities for Fibonacci and Lucas quaternions. The identities are a worthy addition to the literature. Moreover, we give Catalan's identity for the Lucas quaternions.
Kiliç, Emrah, Tan, Elif (2010)
Integers
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Horst Alzer, Florian Luca (2022)
Mathematica Bohemica
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We extend an inequality for Fibonacci numbers published by P. G. Popescu and J. L. Díaz-Barrero in 2006.
Law, Hiu-Fai (2010)
The Electronic Journal of Combinatorics [electronic only]
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Šuniḱ, Zoran (2003)
The Electronic Journal of Combinatorics [electronic only]
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Urszula Bednarz, Iwona Włoch (2018)
Discussiones Mathematicae Graph Theory
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In this paper we shall show applications of the Fibonacci numbers in edge-coloured trees. In particular we determine the successive extremal graphs in the class of trees with respect to the number of (A, 2B)-edge colourings. We show connections between these numbers and Fibonacci numbers as well as the telephone numbers.
Alameddine, A.F. (1991)
International Journal of Mathematics and Mathematical Sciences
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Randic, M., Morales, D., Araujo, O. (2008)
Divulgaciones Matemáticas
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Pavol Híc, Roman Nedela (1998)
Mathematica Slovaca
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Jernej Azarija (2013)
Discussiones Mathematicae Graph Theory
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Let G1 and G2 be simple graphs and let n1 = |V (G1)|, m1 = |E(G1)|, n2 = |V (G2)| and m2 = |E(G2)|. In this paper we derive sharp upper and lower bounds for the number of spanning trees τ in the Cartesian product G1 □G2 of G1 and G2. We show that: [...] and [...] . We also characterize the graphs for which equality holds. As a by-product we derive a formula for the number of spanning trees in Kn1 □Kn2 which turns out to be [...] .