Let $F$ and $G$ be distributions in $𝒟^{'}$ and let $f$ be an infinitely differentiable function with $f^{'} (x) > 0$ , (or $< 0$ ). It is proved that if the neutrix product $F \circ G$ exists and equals $H$ , then the neutrix product $F (f) \circ G (f)$ exists and equals $H (f)$ .

Results on the commutative neutrix convolution product of distributions

Brian Fisher; Emin Özçag — 1993

Archivum Mathematicum

A commutative neutrix convolution of distributions and the exchange formula

Brian Fisher; Emin Özçag; Li Chen Kuan — 1992

Archivum Mathematicum

Page 1

Download Results (CSV)

Advanced Search

Formula preview

Currently displaying 1 – 6 of 6

On the composition of distributions x - s ln | x | and | x | μ .

On the noncommutative neutrix product of distributions.

The Neutrix Convolution Product x -r,- ○ x μ,+

Some results on the product of distributions and the change of variable

Results on the commutative neutrix convolution product of distributions

A commutative neutrix convolution of distributions and the exchange formula

On the composition of distributions $x^{- s} ln | x |$ and ${| x |}^{μ}$ .