Frankl’s conjecture for large semimodular and planar semimodular lattices

Gábor Czédli; E. Tamás Schmidt

Acta Universitatis Palackianae Olomucensis. Facultas Rerum Naturalium. Mathematica (2008)

  • Volume: 47, Issue: 1, page 47-53
  • ISSN: 0231-9721

Abstract

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A lattice L is said to satisfy (the lattice theoretic version of) Frankl’s conjecture if there is a join-irreducible element f L such that at most half of the elements x of L satisfy f x . Frankl’s conjecture, also called as union-closed sets conjecture, is well-known in combinatorics, and it is equivalent to the statement that every finite lattice satisfies Frankl’s conjecture. Let m denote the number of nonzero join-irreducible elements of L . It is well-known that L consists of at most 2 m elements. Let us say that L is large if it has more than 5 · 2 m - 3 elements. It is shown that every large semimodular lattice satisfies Frankl’s conjecture. The second result states that every finite semimodular planar lattice L satisfies Frankl’s conjecture. If, in addition, L has at least four elements and its largest element is join-reducible then there are at least two choices for the above-mentioned f .

How to cite

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Czédli, Gábor, and Schmidt, E. Tamás. "Frankl’s conjecture for large semimodular and planar semimodular lattices." Acta Universitatis Palackianae Olomucensis. Facultas Rerum Naturalium. Mathematica 47.1 (2008): 47-53. <http://eudml.org/doc/32473>.

@article{Czédli2008,
abstract = {A lattice $L$ is said to satisfy (the lattice theoretic version of) Frankl’s conjecture if there is a join-irreducible element $f\in L$ such that at most half of the elements $x$ of $L$ satisfy $f\le x$. Frankl’s conjecture, also called as union-closed sets conjecture, is well-known in combinatorics, and it is equivalent to the statement that every finite lattice satisfies Frankl’s conjecture. Let $m$ denote the number of nonzero join-irreducible elements of $L$. It is well-known that $L$ consists of at most $2^m$ elements. Let us say that $L$ is large if it has more than $5\cdot 2^\{m-3\}$ elements. It is shown that every large semimodular lattice satisfies Frankl’s conjecture. The second result states that every finite semimodular planar lattice $L$ satisfies Frankl’s conjecture. If, in addition, $L$ has at least four elements and its largest element is join-reducible then there are at least two choices for the above-mentioned $f$.},
author = {Czédli, Gábor, Schmidt, E. Tamás},
journal = {Acta Universitatis Palackianae Olomucensis. Facultas Rerum Naturalium. Mathematica},
keywords = {union-closed sets; Frankl’s conjecture; lattice; semimodularity; planar lattice; Frankl's conjecture; union-closed sets conjecture; finite lattice; join-irreducible elementsfinit semimodular planar lattices; semimodularity},
language = {eng},
number = {1},
pages = {47-53},
publisher = {Palacký University Olomouc},
title = {Frankl’s conjecture for large semimodular and planar semimodular lattices},
url = {http://eudml.org/doc/32473},
volume = {47},
year = {2008},
}

TY - JOUR
AU - Czédli, Gábor
AU - Schmidt, E. Tamás
TI - Frankl’s conjecture for large semimodular and planar semimodular lattices
JO - Acta Universitatis Palackianae Olomucensis. Facultas Rerum Naturalium. Mathematica
PY - 2008
PB - Palacký University Olomouc
VL - 47
IS - 1
SP - 47
EP - 53
AB - A lattice $L$ is said to satisfy (the lattice theoretic version of) Frankl’s conjecture if there is a join-irreducible element $f\in L$ such that at most half of the elements $x$ of $L$ satisfy $f\le x$. Frankl’s conjecture, also called as union-closed sets conjecture, is well-known in combinatorics, and it is equivalent to the statement that every finite lattice satisfies Frankl’s conjecture. Let $m$ denote the number of nonzero join-irreducible elements of $L$. It is well-known that $L$ consists of at most $2^m$ elements. Let us say that $L$ is large if it has more than $5\cdot 2^{m-3}$ elements. It is shown that every large semimodular lattice satisfies Frankl’s conjecture. The second result states that every finite semimodular planar lattice $L$ satisfies Frankl’s conjecture. If, in addition, $L$ has at least four elements and its largest element is join-reducible then there are at least two choices for the above-mentioned $f$.
LA - eng
KW - union-closed sets; Frankl’s conjecture; lattice; semimodularity; planar lattice; Frankl's conjecture; union-closed sets conjecture; finite lattice; join-irreducible elementsfinit semimodular planar lattices; semimodularity
UR - http://eudml.org/doc/32473
ER -

References

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