Alexander duality in intersection theory
The number of reducible hypersurfaces in a pencil.
The number of reducible hypersurfaces in a pencil (Erratum).
Intersection theory on algebraic stacks and on their moduli spaces.
Incollamento di punti chiusi e gruppo fondamentale algebrico e topologico
A genericity theorem for algebraic stacks and essential dimension of hypersurfaces
We compute the essential dimension of the functors Forms and Hypersurf of equivalence classes of homogeneous polynomials in variables and hypersurfaces in , respectively, over any base field of characteristic . Here two polynomials (or hypersurfaces) over are considered equivalent if they are related by a linear change of coordinates with coefficients in . Our proof is based on a new Genericity Theorem for algebraic stacks, which is of independent interest. As another application of the...
On the Chow rings of classifying spaces for classical groups
Tame stacks in positive characteristic
We introduce and study a class of algebraic stacks with finite inertia in positive and mixed characteristic, which we call tame algebraic stacks. They include tame Deligne-Mumford stacks, and are arguably better behaved than general Deligne-Mumford stacks. We also give a complete characterization of finite flat linearly reductive schemes over an arbitrary base. Our main result is that tame algebraic stacks are étale locally quotient by actions of linearly reductive finite group schemes.
Corrigendum to : « Tame stacks in positive characteristic »
Essential dimension of moduli of curves and other algebraic stacks
In this paper we consider questions of the following type. Let be a base field and be a field extension. Given a geometric object over a field (e.g. a smooth curve of genus ), what is the least transcendence degree of a field of definition of over the base field ? In other words, how many independent parameters are needed to define ? To study these questions we introduce a notion of essential dimension for an algebraic stack. Using the resulting theory, we give a complete answer to...
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