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On the Riemann-Hilbert problem in multiply connected domains

Vladimir Ryazanov — 2016

Open Mathematics

We proved the existence of multivalent solutions with the infinite number of branches for the Riemann-Hilbert problem in the general settings of finitely connected domains bounded by mutually disjoint Jordan curves, measurable coefficients and measurable boundary data. The theorem is formulated in terms of harmonic measure and principal asymptotic values. It is also given the corresponding reinforced criterion for domains with rectifiable boundaries stated in terms of the natural parameter and nontangential...

On a theorem of Lindelöf

Vladimir GutlyanskiiOlli MartioVladimir Ryazanov — 2011

Annales UMCS, Mathematica

We give a quasiconformal version of the proof for the classical Lindelöf theorem: Let f map the unit disk D conformally onto the inner domain of a Jordan curve C. Then C is smooth if and only if arh f'(z) has a continuous extension to D. Our proof does not use the Poisson integral representation of harmonic functions in the unit disk.

Linear distortion of Hausdorff dimension and Cantor's function.

Oleksiy DovgosheyVladimir RyazanovOlli MartioMatti Vuorinen — 2006

Collectanea Mathematica

Let be a mapping from a metric space X to a metric space Y, and let α be a positive real number. Write dim (E) and H(E) for the Hausdorff dimension and the s-dimensional Hausdorff measure of a set E. We give sufficient conditions that the equality dim (f(E)) = αdim (E) holds for each E ⊆ X. The problem is studied also for the Cantor ternary function G. It is shown that there is a subset M of the Cantor ternary set such that H(M) = 1, with s = log2/log3 and dim(G(E)) = (log3/log2) dim (E), for every...

On a theorem of Lindelof

Vladimir Ya. GutlyanskiiOlli MartioVladimir Ryazanov — 2011

Annales Universitatis Mariae Curie-Skłodowska, sectio A – Mathematica

We give a quasiconformal version of the proof for the classical Lindelof theorem: Let f map the unit disk 𝔻 conformally onto the inner domain of a Jordan curve 𝒞 : Then 𝒞 is smooth if and only if arg f ' ( z ) has a continuous extension to 𝔻 ¯ . Our proof does not use the Poisson integral representation of harmonic functions in the unit disk.

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