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The terms of the form 7kx² in the generalized Lucas sequence with parameters P and Q

Olcay Karaatlı (2016)

Acta Arithmetica

Let Vₙ(P,Q) denote the generalized Lucas sequence with parameters P and Q. For all odd relatively prime values of P and Q such that P² + 4Q > 0, we determine all indices n such that Vₙ(P,Q) = 7kx² when k|P. As an application, we determine all indices n such that the equation Vₙ = 21x² has solutions.

Tribonacci modulo 2 t and 11 t

Jiří Klaška (2008)

Mathematica Bohemica

Our previous research was devoted to the problem of determining the primitive periods of the sequences ( G n mod p t ) n = 1 where ( G n ) n = 1 is a Tribonacci sequence defined by an arbitrary triple of integers. The solution to this problem was found for the case of powers of an arbitrary prime p 2 , 11 . In this paper, which could be seen as a completion of our preceding investigation, we find solution for the case of singular primes p = 2 , 11 .

Tribonacci modulo p t

Jiří Klaška (2008)

Mathematica Bohemica

Our research was inspired by the relations between the primitive periods of sequences obtained by reducing Tribonacci sequence by a given prime modulus p and by its powers p t , which were deduced by M. E. Waddill. In this paper we derive similar results for the case of a Tribonacci sequence that starts with an arbitrary triple of integers.

Truncatable primes and unavoidable sets of divisors

Artūras Dubickas (2006)

Acta Mathematica Universitatis Ostraviensis

We are interested whether there is a nonnegative integer u 0 and an infinite sequence of digits u 1 , u 2 , u 3 , in base b such that the numbers u 0 b n + u 1 b n - 1 + + u n - 1 b + u n , where n = 0 , 1 , 2 , , are all prime or at least do not have prime divisors in a finite set of prime numbers S . If any such sequence contains infinitely many elements divisible by at least one prime number p S , then we call the set S unavoidable with respect to b . It was proved earlier that unavoidable sets in base b exist if b { 2 , 3 , 4 , 6 } , and that no unavoidable set exists in base b = 5 . Now, we prove...

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