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Following a problem posed by Lovász in 1969, it is believed that every finite connected vertex-transitive graph has a Hamilton path. This is shown here to be true for cubic Cayley graphs arising from finite groups having a $(2,s,3)$-presentation, that is, for groups $G=\langle a,b\mid a^2=1,b^s=1,{\left(ab\right)}^3=1,\cdots \rangle$ generated by an involution $a$ and an element $b$ of order $s\ge 3$ such that their product $ab$ has order $3$. More precisely, it is shown that the Cayley graph $X=Cay(G,\{a,b,b^{-1}\})$ has a Hamilton cycle when $\left|G\right|$ (and thus $s$) is congruent to 2 modulo 4, and has a long cycle missing...