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The mean values of logarithms of algebraic integers

Artūras Dubickas — 1998

Journal de théorie des nombres de Bordeaux

Let α be an algebraic integer of degree d with conjugates α 1 = α , α 2 , , α d . In the paper we give a lower bound for the mean value M p ( α ) = 1 d i = 1 d | log | α i | | p p when α is not a root of unity and p > 1 .

Density of some sequences modulo 1

Artūras Dubickas — 2012

Colloquium Mathematicae

Recently, Cilleruelo, Kumchev, Luca, Rué and Shparlinski proved that for each integer a ≥ 2 the sequence of fractional parts a / n n = 1 is everywhere dense in the interval [0,1]. We prove a similar result for all Pisot numbers and Salem numbers α and show that for each c > 0 and each sufficiently large N, every subinterval of [0,1] of length c N - 0 . 475 contains at least one fractional part Q(αⁿ)/n, where Q is a nonconstant polynomial in ℤ[z] and n is an integer satisfying 1 ≤ n ≤ N.

Heights of squares of Littlewood polynomials and infinite series

Artūras Dubickas — 2012

Annales Polonici Mathematici

Let P be a unimodular polynomial of degree d-1. Then the height H(P²) of its square is at least √(d/2) and the product L(P²)H(P²), where L denotes the length of a polynomial, is at least d². We show that for any ε > 0 and any d ≥ d(ε) there exists a polynomial P with ±1 coefficients of degree d-1 such that H(P²) < (2+ε)√(dlogd) and L(P²)H(P²)< (16/3+ε)d²log d. A similar result is obtained for the series with ±1 coefficients. Let A m be the mth coefficient of the square f(x)² of a unimodular...

Squares and cubes in Sturmian sequences

Artūras Dubickas — 2009

RAIRO - Theoretical Informatics and Applications

We prove that every Sturmian word has infinitely many prefixes of the form , where and lim In passing, we give a very simple proof of the known fact that every Sturmian word begins in arbitrarily long squares.

Mahler measures in a cubic field

Artūras Dubickas — 2006

Czechoslovak Mathematical Journal

We prove that every cyclic cubic extension E of the field of rational numbers contains algebraic numbers which are Mahler measures but not the Mahler measures of algebraic numbers lying in E . This extends the result of Schinzel who proved the same statement for every real quadratic field E . A corresponding conjecture is made for an arbitrary non-totally complex field E and some numerical examples are given. We also show that every natural power of a Mahler measure is a Mahler measure.

Truncatable primes and unavoidable sets of divisors

Artūras Dubickas — 2006

Acta Mathematica Universitatis Ostraviensis

We are interested whether there is a nonnegative integer u 0 and an infinite sequence of digits u 1 , u 2 , u 3 , in base b such that the numbers u 0 b n + u 1 b n - 1 + + u n - 1 b + u n , where n = 0 , 1 , 2 , , are all prime or at least do not have prime divisors in a finite set of prime numbers S . If any such sequence contains infinitely many elements divisible by at least one prime number p S , then we call the set S unavoidable with respect to b . It was proved earlier that unavoidable sets in base b exist if b { 2 , 3 , 4 , 6 } , and that no unavoidable set exists in base b = 5 . Now, we prove...

On the limit points of the fractional parts of powers of Pisot numbers

Artūras Dubickas — 2006

Archivum Mathematicum

We consider the sequence of fractional parts { ξ α n } , n = 1 , 2 , 3 , , where α > 1 is a Pisot number and ξ ( α ) is a positive number. We find the set of limit points of this sequence and describe all cases when it has a unique limit point. The case, where ξ = 1 and the unique limit point is zero, was earlier described by the author and Luca, independently.

Nonreciprocal algebraic numbers of small measure

Artūras Dubickas — 2004

Commentationes Mathematicae Universitatis Carolinae

The main result of this paper implies that for every positive integer d 2 there are at least ( d - 3 ) 2 / 2 nonconjugate algebraic numbers which have their Mahler measures lying in the interval ( 1 , 2 ) . These algebraic numbers are constructed as roots of certain nonreciprocal quadrinomials.

On degrees of three algebraic numbers with zero sum or unit product

Paulius DrungilasArtūras Dubickas — 2016

Colloquium Mathematicae

Let α, β and γ be algebraic numbers of respective degrees a, b and c over ℚ such that α + β + γ = 0. We prove that there exist algebraic numbers α₁, β₁ and γ₁ of the same respective degrees a, b and c over ℚ such that α₁ β₁ γ₁ = 1. This proves a previously formulated conjecture. We also investigate the problem of describing the set of triplets (a,b,c) ∈ ℕ³ for which there exist finite field extensions K/k and L/k (of a fixed field k) of degrees a and b, respectively, such that the degree of the...

Multiplicative dependence of shifted algebraic numbers

Paulius DrungilasArtūras Dubickas — 2003

Colloquium Mathematicae

We show that the set obtained by adding all sufficiently large integers to a fixed quadratic algebraic number is multiplicatively dependent. So also is the set obtained by adding rational numbers to a fixed cubic algebraic number. Similar questions for algebraic numbers of higher degrees are also raised. These are related to the Prouhet-Tarry-Escott type problems and can be applied to the zero-distribution and universality of some zeta-functions.

Nonreciprocal algebraic numbers of small Mahler's measure

Artūras DubickasJonas Jankauskas — 2013

Acta Arithmetica

We prove that there exist at least cd⁵ monic irreducible nonreciprocal polynomials with integer coefficients of degree at most d whose Mahler measures are smaller than 2, where c is some absolute positive constant. These polynomials are constructed as nonreciprocal divisors of some Newman hexanomials 1 + x r + + x r , where the integers 1 ≤ r₁ < ⋯ < r₅ ≤ d satisfy some restrictions including 2 r j < r j + 1 for j = 1,2,3,4. This result improves the previous lower bound cd³ and seems to be closer to the correct value of...

Linear recurrence sequences without zeros

Artūras DubickasAivaras Novikas — 2014

Czechoslovak Mathematical Journal

Let a d - 1 , , a 0 , where d and a 0 0 , and let X = ( x n ) n = 1 be a sequence of integers given by the linear recurrence x n + d = a d - 1 x n + d - 1 + + a 0 x n for n = 1 , 2 , 3 , . We show that there are a prime number p and d integers x 1 , , x d such that no element of the sequence X = ( x n ) n = 1 defined by the above linear recurrence is divisible by p . Furthermore, for any nonnegative integer s there is a prime number p 3 and d integers x 1 , , x d such that every element of the sequence X = ( x n ) n = 1 defined as above modulo p belongs to the set { s + 1 , s + 2 , , p - s - 1 } .

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