We show that there exist infinitely many positive integers r not of the form (p-1)/2 - ϕ(p-1), thus providing an affirmative answer to a question of Neville Robbins.

Let ℤ be the set of integers, and let (m,n) be the greatest common divisor of integers m and n. Let p be a prime of the form 4k+1 and p = c²+d² with c,d ∈ ℤ, $d=2^{r}d₀$ and c ≡ d₀ ≡ 1 (mod 4). In the paper we determine ${(b+\surd (b²+4^{\alpha })/2)}^{(p-1)/4)}\left(modp\right)$ for p = x²+(b²+4α)y² (b,x,y ∈ ℤ, 2∤b), and ${(2a+\surd 4a²+1)}^{(p-1)/4}\left(modp\right)$ for p = x²+(4a²+1)y² (a,x,y∈ℤ) on the condition that (c,x+d) = 1 or (d₀,x+c) = 1. As applications we obtain the congruence for $U_{(p-1)/4}\left(modp\right)$ and the criterion for $p|U_{(p-1)/8}$ (if p ≡ 1 (mod 8)), where Uₙ is the Lucas sequence given by U₀ = 0, U₁ = 1 and $U_{n+1}=bUₙ+U_{n-1}\left(n\ge 1\right)$, and b ≢...

For any two positive integers $n$ and $k\ge 2$, let $G(n,k)$ be a digraph whose set of vertices is $\{0,1,...,n-1\}$ and such that there is a directed edge from a vertex $a$ to a vertex $b$ if $a^k\equiv b(modn)$. Let $n={\prod }_{i=1}^r{p}_i^{e_i}$ be the prime factorization of $n$. Let $P$ be the set of all primes dividing $n$ and let $P_1,P_2\subseteq P$ be such that $P_1\cup P_2=P$ and $P_1\cap P_2=\varnothing$. A fundamental constituent of $G(n,k)$, denoted by $G_{P_2}^{*}(n,k)$, is a subdigraph of $G(n,k)$ induced on the set of vertices which are multiples of ${\prod }_{p_i\in P_2}{p}_i$ and are relatively prime to all primes $q\in P_1$. L. Somer and M. Křížek proved that the trees attached to all cycle...

We prove two supercongruences involving Almkvist-Zudilin sequences, which were originally conjectured by Z.-H. Sun (2020).