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Lucas balancing numbers

Kálmán Liptai (2006)

Acta Mathematica Universitatis Ostraviensis

A positive n is called a balancing number if 1 + 2 + + ( n - 1 ) = ( n + 1 ) + ( n + 2 ) + + ( n + r ) . We prove that there is no balancing number which is a term of the Lucas sequence.

Lucas factoriangular numbers

Bir Kafle, Florian Luca, Alain Togbé (2020)

Mathematica Bohemica

We show that the only Lucas numbers which are factoriangular are 1 and 2 .

Lucas partitions.

Robbins, Neville (1998)

International Journal of Mathematics and Mathematical Sciences

Lucas sequences and repdigits

Hayder Raheem Hashim, Szabolcs Tengely (2022)

Mathematica Bohemica

Let ( G n ) n 1 be a binary linear recurrence sequence that is represented by the Lucas sequences of the first and second kind, which are { U n } and { V n } , respectively. We show that the Diophantine equation G n = B · ( g l m - 1 ) / ( g l - 1 ) has only finitely many solutions in n , m + , where g 2 , l is even and 1 B g l - 1 . Furthermore, these solutions can be effectively determined by reducing such equation to biquadratic elliptic curves. Then, by a result of Baker (and its best improvement due to Hajdu and Herendi) related to the bounds of the integral points on...

Mersenne numbers as a difference of two Lucas numbers

Murat Alan (2022)

Commentationes Mathematicae Universitatis Carolinae

Let ( L n ) n 0 be the Lucas sequence. We show that the Diophantine equation L n - L m = M k has only the nonnegative integer solutions ( n , m , k ) = ( 2 , 0 , 1 ) , ( 3 , 1 , 2 ) , ( 3 , 2 , 1 ) , ( 4 , 3 , 2 ) , ( 5 , 3 , 3 ) , ( 6 , 2 , 4 ) , ( 6 , 5 , 3 ) where M k = 2 k - 1 is the k th Mersenne number and n > m .

Multiplicatively dependent triples of Tribonacci numbers

Carlos Alexis Ruiz Gómez, Florian Luca (2015)

Acta Arithmetica

We consider the Tribonacci sequence T : = T n n 0 given by T₀ = 0, T₁ = T₂ = 1 and T n + 3 = T n + 2 + T n + 1 + T n for all n ≥ 0, and we find all triples of Tribonacci numbers which are multiplicatively dependent.

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