Given an integer $n\ge 3$, let $u_1,...,u_n$ be pairwise coprime integers $\ge 2$, $𝒟$ a family of nonempty proper subsets of $\{1,...,n\}$ with “enough” elements, and $\epsilon$ a function $𝒟\to \{\pm 1\}$. Does there exist at least one prime $q$ such that $q$ divides ${\prod }_{i\in I}{u}_i-\epsilon \left(I\right)$ for some $I\in 𝒟$, but it does not divide $u_1\cdots u_n$? We answer this question in the positive when the $u_i$ are prime powers and $\epsilon$ and $𝒟$ are subjected to certain restrictions.We use the result to prove that, if ${\epsilon }_0\in \{\pm 1\}$ and $A$ is a set of three or more primes that contains all prime divisors of any number of the form ${\prod }_{p\in B}p-{\epsilon }_0$ for...

Let $f\left(X\right)\in \mathbb{Q}\left[X\right]$ be a monic polynomial which is a power of a polynomial $g\left(X\right)\in \mathbb{Q}\left[X\right]$ of degree $\mu \ge 2$ and having simple real roots. For given positive integers $d_1,d_2,\ell ,m$ with $\ell \<m$ and gcd$(\ell ,m)=1$ with $\mu \le m+1$ whenever $m\<2$, we show that the equation$$f\left(x\right)f(x+d_1)\cdots f(x+(\ell k-1)d_1)=f\left(y\right)f(y+d_2)\cdots f(y+(mk-1)d_2)$$with $f(x+j{d}_1)\ne 0$ for $0\le j\<\ell k$ has only finitely many solutions in integers $x,y$ and $k\ge 1$ except in the case$$m=\mu =2,\ell =k=d_2=1,f\left(X\right)=g\left(X\right),x=f\left(y\right)+y.$$

For any positive integer $k\ge 2$, let ${\left(P_n^{\left(k\right)}\right)}_{n\ge 2-k}$ be the $k$-generalized Pell sequence which starts with $0,\cdots ,0,1$ ($k$ terms) with the linear recurrence $$P_n^{\left(k\right)}=2P_{n-1}^{\left(k\right)}+P_{n-2}^{\left(k\right)}+\cdots +P_{n-k}^{\left(k\right)}\text{for}n\ge 2.$$ Let ${\left(N_n\right)}_{n\ge 0}$ be Narayana’s sequence given by $$N_0=N_1=N_2=1\text{and}{N}_{n+3}=N_{n+2}+N_n.$$ The purpose of this paper is to determine all $k$-Pell numbers which are sums of two Narayana’s numbers. More precisely, we study the Diophantine equation $$P_p^{\left(k\right)}=N_n+N_m$$ in nonnegative integers $k$, $p$, $n$ and $m$.

Let $k\ge 2$ and let ${\left(P_n^{\left(k\right)}\right)}_{n\ge 2-k}$ be the $k$-generalized Pell sequence defined by $$P_n^{\left(k\right)}=2P_{n-1}^{\left(k\right)}+P_{n-2}^{\left(k\right)}+\cdots +P_{n-k}^{\left(k\right)}$$ for $n\ge 2$ with initial conditions $$P_{-(k-2)}^{\left(k\right)}=P_{-(k-3)}^{\left(k\right)}=\cdots =P_{-1}^{\left(k\right)}=P_0^{\left(k\right)}=0,P_1^{\left(k\right)}=1.$$ In this study, we handle the equation $P_n^{\left(k\right)}=y^m$ in positive integers $n$, $m$, $y$, $k$ such that $k,y\ge 2,$ and give an upper bound on $n.$ Also, we will show that the equation $P_n^{\left(k\right)}=y^m$ with $2\le y\le 1000$ has only one solution given by $P_7^{\left(2\right)}={13}^2.$