Following a problem posed by Lovász in 1969, it is believed that every finite connected vertex-transitive graph has a Hamilton path. This is shown here to be true for cubic Cayley graphs arising from finite groups having a $(2,s,3)$-presentation, that is, for groups $G=\langle a,b\mid a^2=1,b^s=1,{\left(ab\right)}^3=1,\cdots \rangle$ generated by an involution $a$ and an element $b$ of order $s\ge 3$ such that their product $ab$ has order $3$. More precisely, it is shown that the Cayley graph $X=Cay(G,\{a,b,b^{-1}\})$ has a Hamilton cycle when $\left|G\right|$ (and thus $s$) is congruent to 2 modulo 4, and has a long cycle missing...

Let $X$ be a finite simple undirected graph with a subgroup $G$ of the full automorphism group $\mathrm{Aut}\left(X\right)$. Then $X$ is said to be $(G,s)$-transitive for a positive integer $s$, if $G$ is transitive on $s$-arcs but not on $(s+1)$-arcs, and $s$-transitive if it is $\left(\mathrm{Aut}\right(X),s)$-transitive. Let $G_v$ be a stabilizer of a vertex $v\in V\left(X\right)$ in $G$. Up to now, the structures of vertex stabilizers $G_v$ of cubic, tetravalent or pentavalent $(G,s)$-transitive graphs are known. Thus, in this paper, we give the structure of the vertex stabilizers $G_v$ of connected hexavalent $(G,s)$-transitive...