Modulus of smoothness and theorems concerning approximation on compact groups.
Let p,q be positive integers. The groups and act on the Heisenberg group canonically as groups of automorphisms, where is the vector space of all complex p × q matrices. The associated orbit spaces may be identified with and respectively, being the cone of positive semidefinite matrices and the Weyl chamber . In this paper we compute the associated convolutions on and explicitly, depending on p. Moreover, we extend these convolutions by analytic continuation to series of convolution...
Dans cet article, en utilisant les algèbres de Jordan euclidiennes, nous étudions l’espace de Hardy d’un espace symétrique de type Cayley . Nous montrons que le noyau de Cauchy-Szegö de s’exprime comme somme d’une série faisant intervenir la fonction de Harish-Chandra de l’espace symétrique riemannien , la fonction de l’espace symétrique -dual de et les fonctions sphériques de l’espace symétrique ordonné . Nous établissons, dans le cas où la dimension de l’algèbre de Jordan associée...
We study the absolute continuity of the convolution of two orbital measures on the symmetric space SO₀(p,q)/SO(p)×SO(q), q > p. We prove sharp conditions on X,Y ∈ for the existence of the density of the convolution measure. This measure intervenes in the product formula for the spherical functions. We show that the sharp criterion developed for SO₀(p,q)/SO(p)×SO(q) also serves for the spaces SU(p,q)/S(U(p)×U(q)) and Sp(p,q)/Sp(p)×Sp(q), q > p. We moreover apply our results to the study of...
We show that each group in a class of finitely generated groups introduced in [2] and [3] has Kazhdan’s property (T), and calculate the exact Kazhdan constant of with respect to its natural set of generators. These are the first infinite groups shown to have property (T) without making essential use of the theory of representations of linear groups, and the first infinite groups with property (T) for which the exact Kazhdan constant has been calculated. These groups therefore provide answers...