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Trivialité du 2 -rang du noyau hilbertien

Hervé Thomas (1994)

Journal de théorie des nombres de Bordeaux

We give exhaustive list of biquadratic fields K = ( i , m ) and K = ( 2 , m ) without 2 -exotic symbol, i.e. for which the 2 -rank of the Hilbert kernel (or wild kernel) is zero. Such K = ( i , m ) are logarithmic principals [J3]. We detail an exemple of this technical numerical exploration and quote the family of theories and results we utilize. The 2 -rank of tame, regular and wild kernel of K -theory are connected with local and global problem of embedding in a Z 2 -extension. Global class field theory can describe the 2 -rank of the Hilbert...

Unit indices and cohomology for biquadratic extensions of imaginary quadratic fields

Marcin Mazur, Stephen V. Ullom (2008)

Journal de Théorie des Nombres de Bordeaux

We investigate as Galois module the unit group of biquadratic extensions L / M of number fields. The 2 -rank of the first cohomology group of units of L / M is computed for general M . For M imaginary quadratic we determine a large portion of the cases (including all unramified L / M ) where the index [ V : V 1 V 2 V 3 ] takes its maximum value 8 , where V are units mod torsion of L and V i are units mod torsion of one of the 3 quadratic subfields of L / M .

Unités d’une famille de corps liés à la courbe X 1 ( 25 )

Odile Lecacheux (1990)

Annales de l'institut Fourier

On étudie une famille de corps réels cycliques de degré 10 liés à la courbe modulaire X 1 ( 25 ) . Les unités modulaires déterminent un sous-groupe d’unités d’indice fini. Sous certaines conditions, cet indice est égal à 1 ou 5.

When is the order generated by a cubic, quartic or quintic algebraic unit Galois invariant: three conjectures

Stéphane R. Louboutin (2020)

Czechoslovak Mathematical Journal

Let ε be an algebraic unit of the degree n 3 . Assume that the extension ( ε ) / is Galois. We would like to determine when the order [ ε ] of ( ε ) is Gal ( ( ε ) / ) -invariant, i.e. when the n complex conjugates ε 1 , , ε n of ε are in [ ε ] , which amounts to asking that [ ε 1 , , ε n ] = [ ε ] , i.e., that these two orders of ( ε ) have the same discriminant. This problem has been solved only for n = 3 by using an explicit formula for the discriminant of the order [ ε 1 , ε 2 , ε 3 ] . However, there is no known similar formula for n > 3 . In the present paper, we put forward and motivate three...

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